From binoy@ccs.neu.edu Wed Sep 24 22:45:56 1997
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Date: Wed, 24 Sep 1997 22:42:24 -0400
From: Binoy Samuel <binoy@ccs.neu.edu>
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To: Karl Lieberherr <lieber@ccs.neu.edu>
Subject: inlaws ??
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Hi,
I was trying the inlaws problem, but now I'm not very sure whether I
understand how it can be done without join etc.
Could you rephrase the strategy in plain english?
I'm attaching my attempt...

-binoy

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//inlaw.cd

Person = "[" "person"
	<personname> Ident 
	["spouse"<spouse>Person]
	["siblings"<siblings>NList(Person)] 
	"]". 

NList(S) ~ S{S}.

Main=.

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//inlaw.beh

Main {
(@ static public void main(String args[]) throws Exception {
      Person a = Person.parse(System.in);
      a.universal_trv0(new DisplayVisitor());

	System.out.println();
	System.out.println(" display done ");
      	System.out.println("SUCCESS");
  }
@)
}   
 

strategy x =
{	Person -> Person bypassing -> Person,siblings,* 
	Person -> Person bypassing -> Person,spouse,* 

}.


/*
start#Person .
(
  - through -> *,spouse,* and bypassing {Person} to sp#Person . 
  - through -> *,siblings,* and bypassing {Person} to inlaw#Person
  +
  - through -> *,siblings,* and bypassing {Person} to si#Person . 
  - through -> *,spouse,* and bypassing {Person} to inlaw#Person
    )
*/


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